6a^2+15=-19a

Solution for 6a^2+15=-19a equation:

6a^2+15=-19a

We move all terms to the left:

6a^2+15-(-19a)=0

We get rid of parentheses

6a^2+19a+15=0

a = 6; b = 19; c = +15;
Δ = b2-4ac
Δ = 192-4·6·15
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-1}{2*6}=\frac{-20}{12}
=-1+2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+1}{2*6}=\frac{-18}{12}
=-1+1/2
$